# LUT6_2 - 2021.2 English

## Vivado Design Suite 7 Series FPGA and Zynq-7000 SoC Libraries Guide (UG953)

Document ID
UG953
Release Date
2021-10-22
Version
2021.2 English

Primitive: Six-input, 2-output, Look-Up Table

## Introduction

This design element is a 6-input, 2-output look-up table (LUT) that can either act as a dual asynchronous 32-bit ROM (with 5-bit addressing), implement any two 5-input logic functions with shared inputs, or implement a 6-input logic function and a 5-input logic function with shared inputs and shared logic values. LUTs are the basic logic building blocks and are used to implement most logic functions of the design. A LUT6_2 will be mapped to one of the four look-up tables in the slice.

An INIT attribute consisting of a 64-bit hexadecimal value must be specified to indicate the LUTs logical function. The INIT value is calculated by assigning a 1 to corresponding INIT bit value when the associated inputs are applied. For instance, a Verilog INIT value of 64'hfffffffffffffffe (X"FFFFFFFFFFFFFFFE" for VHDL) makes the O6 output 1 unless all zeros are on the inputs and the O5 output a 1, or unless I[4:0] are all zeros (a 5-input and 6-input OR gate). The lower half (bits 31:0) of the INIT values apply to the logic function of the O5 output.

The INIT parameter for the FPGA LUT primitive gives the LUT its logical value. By default, this value is zero, thus driving the output to a zero regardless of the input values (acting as a ground). However, in most cases a new INIT value must be determined to specify the logic function for the LUT primitive. There are at least two methods by which the LUT value can be determined.

• The Logic Table Method: Create a binary logic table of all possible inputs, specify the desired logic value of the output and then create the INIT string from those output values.
• The Equation Method: Define parameters for each input to the LUT that correspond to their listed truth value and use those to build the logic equation you are after. This method is easier to understand once you have grasped the concept and is more self-documenting than the above method. However, this method does require the code to first specify the appropriate parameters.

## Logic Table

Inputs Outputs
I5 I4 I3 I2 I1 I0 O5 O6
0 0 0 0 0 0 INIT[0] INIT[0]
0 0 0 0 0 1 INIT[1] INIT[1]
0 0 0 0 1 0 INIT[2] INIT[2]
0 0 0 0 1 1 INIT[3] INIT[3]
0 0 0 1 0 0 INIT[4] INIT[4]
0 0 0 1 0 1 INIT[5] INIT[5]
0 0 0 1 1 0 INIT[6] INIT[6]
0 0 0 1 1 1 INIT[7] INIT[7]
0 0 1 0 0 0 INIT[8] INIT[8]
0 0 1 0 0 1 INIT[9] INIT[9]
0 0 1 0 1 0 INIT[10] INIT[10]
0 0 1 0 1 1 INIT[11] INIT[11]
0 0 1 1 0 0 INIT[12] INIT[12]
0 0 1 1 0 1 INIT[13] INIT[13]
0 0 1 1 1 0 INIT[14] INIT[14]
0 0 1 1 1 1 INIT[15] INIT[15]
0 1 0 0 0 0 INIT[16] INIT[16]
0 1 0 0 0 1 INIT[17] INIT[17]
0 1 0 0 1 0 INIT[18] INIT[18]
0 1 0 0 1 1 INIT[19] INIT[19]
0 1 0 1 0 0 INIT[20] INIT[20]
0 1 0 1 0 1 INIT[21] INIT[21]
0 1 0 1 1 0 INIT[22] INIT[22]
0 1 0 1 1 1 INIT[23] INIT[23]
0 1 1 0 0 0 INIT[24] INIT[24]
0 1 1 0 0 1 INIT[25] INIT[25]
0 1 1 0 1 0 INIT[26] INIT[26]
0 1 1 0 1 1 INIT[27] INIT[27]
0 1 1 1 0 0 INIT[28] INIT[28]
0 1 1 1 0 1 INIT[29] INIT[29]
0 1 1 1 1 0 INIT[30] INIT[30]
0 1 1 1 1 1 INIT[31] INIT[31]
1 0 0 0 0 0 INIT[0] INIT[32]
1 0 0 0 0 1 INIT[1] INIT[33]
1 0 0 0 1 0 INIT[2] INIT[34]
1 0 0 0 1 1 INIT[3] INIT[35]
1 0 0 1 0 0 INIT[4] INIT[36]
1 0 0 1 0 1 INIT[5] INIT[37]
1 0 0 1 1 0 INIT[6] INIT[38]
1 0 0 1 1 1 INIT[7] INIT[39]
1 0 1 0 0 0 INIT[8] INIT[40]
1 0 1 0 0 1 INIT[9] INIT[41]
1 0 1 0 1 0 INIT[10] INIT[42]
1 0 1 0 1 1 INIT[11] INIT[43]
1 0 1 1 0 0 INIT[12] INIT[44]
1 0 1 1 0 1 INIT[13] INIT[45]
1 0 1 1 1 0 INIT[14] INIT[46]
1 0 1 1 1 1 INIT[15] INIT[47]
1 1 0 0 0 0 INIT[16] INIT[48]
1 1 0 0 0 1 INIT[17] INIT[49]
1 1 0 0 1 0 INIT[18] INIT[50]
1 1 0 0 1 1 INIT[19] INIT[51]
1 1 0 1 0 0 INIT[20] INIT[52]
1 1 0 1 0 1 INIT[21] INIT[53]
1 1 0 1 1 0 INIT[22] INIT[54]
1 1 0 1 1 1 INIT[23] INIT[55]
1 1 1 0 0 0 INIT[24] INIT[56]
1 1 1 0 0 1 INIT[25] INIT[57]
1 1 1 0 1 0 INIT[26] INIT[58]
1 1 1 0 1 1 INIT[27] INIT[59]
1 1 1 1 0 0 INIT[28] INIT[60]
1 1 1 1 0 1 INIT[29] INIT[61]
1 1 1 1 1 0 INIT[30] INIT[62]
1 1 1 1 1 1 INIT[31] INIT[63]
INIT = Binary equivalent of the hexadecimal number assigned to the INIT attribute.

## Port Descriptions

Port Direction Width Function
O6 Output 1 6/5-LUT output.
O5 Output 1 5-LUT output.
I0, I1, I2, I3, I4, I5 Input 1 LUT inputs.

## Design Entry Method

 Instantiation Yes Inference Recommended IP Catalog No Macro support No

## Available Attributes

Attribute Type Allowed Values Default Description
INIT HEX Any 64-Bit Value All zeros Specifies the LUT5/6 output function.

## VHDL Instantiation Template

Unless they already exist, copy the following two statements and paste them before the entity declaration.
``````Library UNISIM;
use UNISIM.vcomponents.all;``````
``````
-- LUT6_2: 6-input  2 output Look-Up Table
--         7 Series
-- Xilinx HDL Language Template, version 2021.2

LUT6_2_inst : LUT6_2
generic map (
INIT => X"0000000000000000") -- Specify LUT Contents
port map (
O6 => O6,  -- 6/5-LUT output (1-bit)
O5 => O5,  -- 5-LUT output (1-bit)
I0 => I0,   -- LUT input (1-bit)
I1 => I1,   -- LUT input (1-bit)
I2 => I2,   -- LUT input (1-bit)
I3 => I3,   -- LUT input (1-bit)
I4 => I4,   -- LUT input (1-bit)
I5 => I5    -- LUT input (1-bit)
);

-- End of LUT6_2_inst instantiation
``````

``````
// LUT6_2: 6-input, 2 output Look-Up Table
//         7 Series
// Xilinx HDL Language Template, version 2021.2

LUT6_2 #(
.INIT(64'h0000000000000000) // Specify LUT Contents
) LUT6_2_inst (
.O6(O6), // 1-bit LUT6 output
.O5(O5), // 1-bit lower LUT5 output
.I0(I0), // 1-bit LUT input
.I1(I1), // 1-bit LUT input
.I2(I2), // 1-bit LUT input
.I3(I3), // 1-bit LUT input
.I4(I4), // 1-bit LUT input
.I5(I5)  // 1-bit LUT input (fast MUX select only available to O6 output)
);

// End of LUT6_2_inst instantiation
``````

## Related Information

• See the 7 Series FPGAs Configurable Logic Block User Guide (UG474).