解聚示例 - 2023.2 简体中文

#define N 10

struct A {
  char c;
  int i;
};

void dut(A in[N], A out[N]) {
#pragma HLS interface axis port=in
#pragma HLS interface axis port=out
#pragma HLS disaggregate variable=in
#pragma HLS disaggregate variable=out
  int sum = 0;
  for (unsigned i=0; i<N; i++) {
    out[i].c = in[i].c;
    out[i].i = in[i].i;
  }
} 

module dut (
ap_local_block,
ap_local_deadlock,
ap_clk,
ap_rst_n,
ap_start,
ap_done,
ap_idle,
ap_ready,
in_c_TVALID,
in_i_TVALID,
out_c_TREADY,
out_i_TREADY,
in_c_TDATA,
in_c_TREADY,
in_i_TDATA,
in_i_TREADY,
out_c_TDATA,
out_c_TVALID,
out_i_TDATA,
out_i_TVALID
);

#define N 1024

struct A {,
  hls::stream<int> s_in;
  long arr[N];
};

long dut(struct A &d) {
  long sum = 0;
  while(!d.s_in.empty())
    sum += d.s_in.read();
  for (unsigned i=0; i<N; i++)
    sum += d.arr[i]; 
  return sum;
}

module dut (
ap_local_block,
ap_local_deadlock,
ap_clk,
ap_rst,
ap_start,
ap_done,
ap_idle,
ap_ready,
d_s_in_dout,
d_s_in_empty_n,
d_s_in_read,
d_arr_ce0, 
d_arr_q0,
ap_return
);